If the goal is just to say if any of the known list appears in userMessage, and you don't care which one it is, use any with a generator expression:
if any(srchstr in userMessage
for srchstr in ('hi', 'hello', 'greetings')):If the words must be found as individual words (so userMessage = "This" should be false, even though hi appears in it), then use:
if not {
'hi',
'hello',
'greetings'
}.isdisjoint(userMessage.split()):You can do:
found = set(['hi', 'hello', 'greetings']) & set(userMessage.split())
for obj in found:
print foundYou can also compare multiple elements using Set:
if set(['hi', 'hello', 'greetings']) <= set(userMessage.split()):
print("Hello!")If the goal is just to say if any of the anycodings_input known list appears in userMessage, and anycodings_input you don't care which one it is, use any anycodings_input with a generator expression:,If the words must be found as individual anycodings_input words (so userMessage = "This" should be anycodings_input false, even though hi appears in it), anycodings_input then use:,It will short-circuit when it gets a anycodings_input hit, so if hi appears in the input, it anycodings_input doesn't check the rest, and immediately anycodings_input returns True.,I tried what's showed above but it says it anycodings_input cannot use lists, it must use a single anycodings_input string. Same thing if I set the array to an anycodings_input object/variable. If I use "or" it doesn't anycodings_input seem to work altogether.
AKA the correct version of this:
if ['hi', 'hello', 'greetings'] in userMessage:
print('Hello!')If the goal is just to say if any of the anycodings_input known list appears in userMessage, and anycodings_input you don't care which one it is, use any anycodings_input with a generator expression:
if any(srchstr in userMessage
for srchstr in ('hi', 'hello', 'greetings')):If the words must be found as individual anycodings_input words (so userMessage = "This" should be anycodings_input false, even though hi appears in it), anycodings_input then use:
if not {
'hi',
'hello',
'greetings'
}.isdisjoint(userMessage.split()):You can do:
found = set(['hi', 'hello', 'greetings']) & set(userMessage.split())
for obj in found:
print foundYou can also compare multiple elements anycodings_input using Set:
if set(['hi', 'hello', 'greetings']) <= set(userMessage.split()):
print("Hello!")This tutorial provides brief information on all keywords used in Python.,in is used to test if a sequence (list, tuple, string etc.) contains a value. It returns True if the value is present, else it returns False. For example:,Unlike list and dictionary, string and tuple are immutable (value cannot be altered once defined). Hence, two equal string or tuple are identical as well. They refer to the same memory location.,is is used in Python for testing object identity. While the == operator is used to test if two variables are equal or not, is is used to test if the two variables refer to the same object.
The above keywords may get altered in different versions of Python. Some extra might get added or some might be removed. You can always get the list of keywords in your current version by typing the following in the prompt.
>>>
import keyword
>>>
print(keyword.kwlist)['False', 'None', 'True', 'and', 'as', 'assert', 'async', 'await', 'break', 'class', 'continue', 'def', 'del', 'elif', 'else', 'except', 'finally', 'for', 'from', 'global', 'if', 'import', 'in', 'is', 'lambda', 'nonlocal', 'not', 'or', 'pass', 'raise', 'return', 'try', 'while', 'with', 'yield']True and False are truth values in Python. They are the results of comparison operations or logical (Boolean) operations in Python. For example:
>>> 1 == 1 True >>> 5 > 3 True >>> True or False True >>> 10 <= 1 False >>> 3 > 7 False >>> True and False False
Here we can see that the first three statements are true so the interpreter returns True and returns False for the remaining three statements. True and False in python is same as 1 and 0. This can be justified with the following example:
>>> True == 1 True >>> False == 0 True >>> True + True 2
Void functions that do not return anything will return a None object automatically. None is also returned by functions in which the program flow does not encounter a return statement. For example:
def a_void_function():
a = 1
b = 2
c = a + b
x = a_void_function()
print(x)Output
NoneLast Updated : 26 Nov, 2018
Examples:
Input: patterns = ['ape', 'apple',
'peach', 'puppy'
],
input = 'appel'
Output: ['apple', 'ape']Output:
['apple', 'ape']The first example is a list of five integers, and the next is a list of three strings. The third is a tuple containing four integers, followed by a tuple containing four strings. The last is a list containing three tuples, each of which contains a pair of strings.,The join method does approximately the oposite of the split method. It takes a list of strings as an argument and returns a string of all the list elements joined together.,The in operator returns whether a given element is contained in a list or tuple:,We will discuss looping in greater detail in the next chapter. For now just note that the colon (:) at the end of the first line and the indentation on the second line are both required for this statement to be syntactically correct.
[10, 20, 30, 40, 50]
["spam", "bungee", "swallow"]
(2, 4, 6, 8)
("two", "four", "six", "eight")[("cheese", "queso"), ("red", "rojo"), ("school", "escuela")]>>> thing = 2, 4, 6, 8
>>> type(thing)
<class 'tuple'>
>>> thing
(2, 4, 6, 8)>>> singleton = (2,)
>>> type(singleton)
<class 'tuple'>
>>> not_tuple = (2)
>>> type(not_tuple)
<class 'int'>
>>> empty_tuple = ()
>>> type(empty_tuple)
<class 'tuple'>>>> fruit = "banana" >>>
fruit[1]
'a' >>>
fruits = ['apples', 'cherries', 'pears'] >>>
fruits[0]
'apples' >>>
prices = (3.99, 6.00, 10.00, 5.25) >>>
prices[3]
5.25
>>>
pairs = [('cheese', 'queso'), ('red', 'rojo'), ('school', 'escuela')] >>>
pairs[2]
('school', 'escuela')>>> len('banana')
6>>> len(['a', 'b', 'c', 'd'])
4
>>>
len((2, 4, 6, 8, 10, 12))
6
>>>
pairs = [('cheese', 'queso'), ('red', 'rojo'), ('school', 'escuela')] >>>
len(pairs)
3If we have a mutable object (list, dict, set, etc.), we can use some specific operations to mutate it and all the variables that refer to it will see the change.,If we have an immutable object (str, int, tuple, etc.), all the variables that refer to it will always see the same value, but operations that transform that value into a new value always return a new object.,If you want to know if two variables refer to the same object or not, you can use the is operator, or the built-in function id().,This is because of a combination of the fact that augmented assignment operators are assignment operators, and the difference between mutable and immutable objects in Python.
>>> x = 10 >>> def bar(): ...print(x) >>> bar() 10
>>> x = 10 >>> def foo(): ...print(x) ...x += 1
>>> foo()
Traceback(most recent call last):
...
UnboundLocalError: local variable 'x'
referenced before assignment>>> x = 10 >>>
def foobar():
...global x
...print(x)
...x += 1 >>>
foobar()
10>>> print(x) 11
>>> def foo():
...x = 10
...def bar():
...nonlocal x
...print(x)
...x += 1
...bar()
...print(x) >>>
foo()
10
11