Let’s start from basic, quickest way to create and initialize a normal list with same values in python is,
# Creating a list with same values list_of_num = [5] * 10 print(list_of_num)
[5, 5, 5, 5, 5, 5, 5, 5, 5, 5]
Let’s inserting an element in the 3rd sub list of main list i.e.
# Insert 11 into the 3 rd sub list
list_of_num[2].append(11)
Let’s insert the element in the 3rd sub list,
# Insert 11 into the 3 rd sub list
list_of_lists[2].append(11)
print(list_of_lists)
Using Python’s range() function, we can generate a sequence of numbers from 0 to n-1 and for each element in the sequence create & append a sub-list to the main list using List Comprehension i.e.
# Create a list of 5 empty sub lists list_of_lists = [ [] for i in range(5) ] print('List of lists:') print(list_of_lists)
Problem: How to create a list of lists by modifying each element of an original list of lists?,Problem: Given a list of lists. How to flatten the list of lists by getting rid of the inner lists—and keeping their elements?,Problem: How to print a list of lists with a new line after each list so that the columns are aligned?,Problem: How to convert a list of lists into a list of tuples?
For example, to create a list of lists of integer values, use [[1, 2], [3, 4]]
. Each list element of the outer list is a nested list itself.
lst = [ [1, 2], [3, 4] ]
Find examples of all three methods in the following code snippet:
lst = [ [1, 2], [3, 4] ] # Method 1: List Comprehension flat_1 = [x for l in lst for x in l ] # Method 2: Unpacking flat_2 = [ * lst[0], * lst[1]] # Method 3: Extend Method flat_3 = [] for l in lst: flat_3.extend(l) # # Check results: print(flat_1) #[1, 2, 3, 4] print(flat_2) #[1, 2, 3, 4] print(flat_3) #[1, 2, 3, 4]
Solution: You can achieve this by using the beautiful (but, surprisingly, little-known) feature of dictionary comprehension in Python.
persons = [ ['Alice', 25, 'blonde'], ['Bob', 33, 'black'], ['Ann', 18, 'purple'] ] persons_dict = { x[0]: x[1: ] for x in persons } print(persons_dict) # { 'Alice': [25, 'blonde'], # 'Bob': [33, 'black'], # 'Ann': [18, 'purple'] }
Here’s the alternative code:
persons = [ ['Alice', 25, 'blonde'], ['Bob', 33, 'black'], ['Ann', 18, 'purple'] ] persons_dict = {} for x in persons: persons_dict[x[0]] = x[1: ] print(persons_dict) # { 'Alice': [25, 'blonde'], # 'Bob': [33, 'black'], # 'Ann': [18, 'purple'] }
Example: Convert the following list of lists
[ [1, 2, 3], [4, 5, 6] ]
Remote Work 2022 , Remote Work 2022
Python provides an option of creating a list within a list. If put simply, it is a nested list but with one or more lists inside as an element.
Here is an example of a list of lists to make things more clear:
[ [a, b], [c, d], [e, f] ]
Input:
# Create 2 independent lists list_1 = [a, b, c] list_2 = [d, e, f] # Create an empty list list = [] # Create List of lists list.append(list_1) list.append(list_2) print(list)
Output:
[ [a, b, c], [d, e, f] ]
Last Updated : 01 Aug, 2022
Output:
["Geeks", "for", "Geeks"]
Blank List: [] List of numbers: [10, 20, 14] List Items: Geeks Geeks
Blank List: [] List of numbers: [10, 20, 14] List Items: Geeks Geeks
List with the use of Numbers: [1, 2, 4, 4, 3, 3, 3, 6, 5]
List with the use of Mixed Values: [1, 2, 'Geeks', 4, 'For', 6, 'Geeks']
Accessing a element from the list
Geeks
Geeks
Accessing a element from a Multi - Dimensional list
For
Geeks