Here you go, You were on the right track! Just need to change the regex to '\d+' from '\d' and add count as 1.
s = 'button id="qty_plus_cartline_change_1221067058" type="button"class="quantity_plus " data-component="quantitybox.inc">+<span class="offscreen">Increase the Quantity 1</span></button' new_string=re.sub('\d+', 'new_number' , s,1) print(new_string)
First, use \d+
to match the whole group of digits instead of individual ones. Then, you can use the count=
argument of re.sub
to limit to 1 replacement:
import re
s = 'button id="qty_plus_cartline_change_1221067058" type="button"class="quantity_plus " data-component="quantitybox.inc">+<span class="offscreen">Increase the Quantity 1</span></button' new_string=re.sub(r'\d+', 'new_number' , s, count=1) print(new_string) # button id="qty_plus_cartline_change_new_number" type="button" class="quantity_plus " data-component="quantitybox.inc">+<span class="offscreen">Increase the Quantity 1</span></button
Last Updated : 24 Jun, 2020
Examples:
Input: str = "Geeksforgeeks", n = 3
Output: ['Gee', 'ksf', 'oor', 'gee', 'ks']
Input: str = "1234567891234567", n = 4
Output: [1234, 5678, 9123, 4567]
['Gee', 'ksf', 'org', 'eek', 's']
['Gee', 'ksf', 'org', 'eek', 's']
['123G', 'eeks', 'ForG', 'eeks', '4567']
The solution is to use Python’s raw string notation for regular expressions; backslashes are not handled in any special way in a string literal prefixed with 'r', so r"\n" is a two-character string containing '\' and 'n', while "\n" is a one-character string containing a newline. Regular expressions will often be written in Python code using this raw string notation.,In addition, special escape sequences that are valid in regular expressions, but not valid as Python string literals, now result in a DeprecationWarning and will eventually become a SyntaxError, which means the sequences will be invalid if raw string notation or escaping the backslashes isn’t used.,The r prefix, making the literal a raw string literal, is needed in this example because escape sequences in a normal “cooked” string literal that are not recognized by Python, as opposed to regular expressions, now result in a DeprecationWarning and will eventually become a SyntaxError. See The Backslash Plague.,This document is an introductory tutorial to using regular expressions in Python with the re module. It provides a gentler introduction than the corresponding section in the Library Reference.
. ^ $ * + ? {} []\ | ()
>>>
import re
>>>
p = re.compile('ab*') >>>
p
re.compile('ab*')
>>> p = re.compile('ab*', re.IGNORECASE)
>>>
import re
>>>
p = re.compile('[a-z]+') >>>
p
re.compile('[a-z]+')
>>> p.match("") >>>
print(p.match(""))
None
>>> m = p.match('tempo')
>>> m
<re.Match object; span=(0, 5), match='tempo'>
Author: Aditya Raj Last Updated: March 10, 2021
For example, we can print first character, third character and eleventh character of an string using the following program. Note that indexing is 0 based in python. i.e. first character is given the index 0 and not 1.
myString = "PythonForBeginners"
x = myString[0]
print(x)
x = myString[2]
print(x)
x = myString[10]
print(x)
Output
P
t
e
In the following example, we use negative indexing for printing characters of a python string.
myString = "PythonForBeginners"
x = myString[-1]
print(x)
x = myString[-5]
print(x)
x = myString[-10]
print(x)
To capture a sub string from starting to a given index we can leave empty the start_index
value.
myString = "PythonForBeginners"
x = myString[: 6]
print(x)
x = myString[: 9]
print(x)
x = myString[: 18]
print(x)
myString = "PythonForBeginners"
x = myString[0: ]
print(x)
x = myString[6: ]
print(x)
x = myString[9: ]
print(x)
The methods of Python's str type give you a powerful set of tools for formatting, splitting, and manipulating string data. But even more powerful tools are available in Python's built-in regular expression module. Regular expressions are a huge topic; there are there are entire books written on the topic (including Jeffrey E.F. Friedl’s Mastering Regular Expressions, 3rd Edition), so it will be hard to do justice within just a single subsection.,Combining these ideas (as well as some of the powerful regexp syntax that we have not covered here) allows you to flexibly and quickly extract information from strings in Python.,If you would like to find a substring and then split the string based on its location, the partition() and/or split() methods are what you're looking for. Both will return a sequence of substrings.,But, you might ask, why would you want to use the more complicated and verbose syntax of regular expressions rather than the more intuitive and simple string methods? The advantage is that regular expressions offer far more flexibility.
x = 'a string'
y = "a string"
x == y
True
multiline = "" " one two three "" "
fox = "tHe qUICk bROWn fOx."
fox.upper()
'THE QUICK BROWN FOX.'