Suppose distMatrix
is your matrix of distances (don't have to be Euclidean), with entry in row i
and column j
representing the distance between the i
th and j
th objects. Then:
# import packages from scipy.cluster import hierarchy import scipy.spatial.distance as ssd import seaborn as sns # define distance array as in linked answer distArray = ssd.squareform(distMatrix) # define linkage object distLinkage = hierarchy.linkage(distArray) # make clustermap sns.clustermap(distMatrix, row_linkage = distLinkage, col_linkage = distLinkage)
Plot a matrix dataset as a hierarchically-clustered heatmap.,Distance metric to use for the data. See scipy.spatial.distance.pdist() documentation for more options. To use different metrics (or methods) for rows and columns, you may construct each linkage matrix yourself and provide them as {row,col}_linkage.,Linkage method to use for calculating clusters. See scipy.cluster.hierarchy.linkage() documentation for more information.,Precomputed linkage matrix for the rows or columns. See scipy.cluster.hierarchy.linkage() for specific formats.
>>>
import seaborn as sns;
sns.set_theme(color_codes = True) >>>
iris = sns.load_dataset("iris") >>>
species = iris.pop("species") >>>
g = sns.clustermap(iris)
>>> g = sns.clustermap(iris, ...figsize = (7, 5), ...row_cluster = False, ...dendrogram_ratio = (.1, .2), ...cbar_pos = (0, .2, .03, .4))
>>> lut = dict(zip(species.unique(), "rbg")) >>>
row_colors = species.map(lut) >>>
g = sns.clustermap(iris, row_colors = row_colors)
>>> g = sns.clustermap(iris, cmap = "mako", vmin = 0, vmax = 10)
>>> g = sns.clustermap(iris, metric = "correlation")
>>> g = sns.clustermap(iris, method = "single")
I want to pass my own distance matrix (row anycodings_seaborn linkages) to seaborn clustermap.,Is there an option where it purely uses my anycodings_seaborn distances and creates the linkages?,My distance matrix is already based on a anycodings_seaborn certain metric and method, why would I want anycodings_seaborn to recalculate this in scipy hierarchy anycodings_seaborn linkage ?,Use Distance Matrix in anycodings_seaborn scipy.cluster.hierarchy.linkage()?
Suppose distMatrix is your matrix of anycodings_hierarchical-clustering distances (don't have to be Euclidean), anycodings_hierarchical-clustering with entry in row i and column j anycodings_hierarchical-clustering representing the distance between the anycodings_hierarchical-clustering ith and jth objects. Then:
# import packages from scipy.cluster import hierarchy import scipy.spatial.distance as ssd import seaborn as sns # define distance array as in linked answer distArray = ssd.squareform(distMatrix) # define linkage object distLinkage = hierarchy.linkage(distArray) # make clustermap sns.clustermap(distMatrix, row_linkage = distLinkage, col_linkage = distLinkage)
See squareform for information on how to calculate the index of this entry or to convert the condensed distance matrix to a redundant square matrix.,converts between condensed distance matrices and square distance matrices.,Computes the normalized Hamming distance, or the proportion of those vector elements between two n-vectors u and v which disagree. To save memory, the matrix X can be of type boolean.,Y = pdist(X, 'hamming') Computes the normalized Hamming distance, or the proportion of those vector elements between two n-vectors u and v which disagree. To save memory, the matrix X can be of type boolean.
dm = pdist(X, lambda u, v: np.sqrt(((u - v) ** 2).sum()))
dm = pdist(X, sokalsneath)
dm = pdist(X, 'sokalsneath')