should i close a file before moving it?

On Windows:

>>> import os
>>> with open('old.txt') as file:
os.rename('old.txt', 'new.txt')

Traceback (most recent call last):
File "<pyshell#4>", line 2, in <module>
      os.rename('test.txt', 'newtest.txt')
      WindowsError: [Error 32] The process cannot access the file because it is being used by another process

yes , I was getting same issue, I was doing some operation in for loop(if rows/content is valid then move destination folder) outside for loop, if no header/no content/no rows then move to error folder and I was getting error I could resolve it using "read_obj.close" jus before filemove method here is the snippet with open(csv_file, 'r') as read_obj:

                # pass the file object to reader() to get the reader object
                csv_dic_reader = csv.DictReader(read_obj)
                data = [row
                   for row in csv_dic_reader
                ]
                for row in data:
                   read_obj.close()
                filesMove(csv_file, destination_file_path, src_file_path)
                if len(data) <= 1: # this will check no rows / content
                read_obj.close()
                filesMove(csv_file, error_file_path, src_file_path)

Suggestion : 2

You need to get out of the loop before moving the file:,I have an issue ttying to move a file using shutil.move(), likely because the file is still open. I don't have the problem when run it in debugger ... But when I execute the script I have this error:, 3 chest logic puzzle, is there something you can say that is guaranteed to give you treasure without the risk of poisoning? ,Here is a block of my code that is causing the issue. How could this be changed to avoid the problem?

You need to get out of the loop before moving the file:

listFile = os.listdir(indir)
os.chdir(indir)

for report in listFile:
   abs_report = os.path.abspath(report)
is_pull = None
for line in open(abs_report):
   if header not in line:
   is_pull = (ref in line)
break
if is_pull is not None:
   if is_pull:
   shutil.move(abs_report, Pull)
logger.write("File " + report + " has been moved to " + Pull + " at " + str(datetime.now()) + "\n")
else:
   shutil.move(abs_report, outdir)
logger.write("File " + report + " has been moved to " + outdir + " at " + str(datetime.now()) + "\n")

Suggestion : 3

So yes, the safest and portable way is anycodings_python to close the file first. Note that with anycodings_python clause closes the file automatically, so anycodings_python all you need is to perform the move anycodings_python outside of with block.,Best practice with file is close and anycodings_python move, because if you will not close then anycodings_python it might be create problem in some OS, anycodings_python like Windows. ,You can't move the file, because anycodings_python someone(you) is already holding it. You anycodings_python need to close the file before you can anycodings_python move it.,To make your code more portable, close anycodings_python file before move.

I have code like this:

with open('foo.txt') as file:
   ...do something with file...
      ...move foo.txt to another place
   while
   it 's still open...

On Windows:

>>> import os
>>> with open('old.txt') as file:
os.rename('old.txt', 'new.txt')

Traceback (most recent call last):
File "<pyshell#4>", line 2, in <module>
      os.rename('test.txt', 'newtest.txt')
      WindowsError: [Error 32] The process cannot access the file because it is being used by another process

yes , I was getting same issue, I was anycodings_python doing some operation in for loop(if anycodings_python rows/content is valid then move anycodings_python destination folder) outside for loop, if anycodings_python no header/no content/no rows then move anycodings_python to error folder and I was getting anycodings_python error I could resolve it using anycodings_python "read_obj.close" jus before filemove anycodings_python method here is the snippet with anycodings_python open(csv_file, 'r') as read_obj:

                # pass the file object to reader() to get the reader object
                csv_dic_reader = csv.DictReader(read_obj)
                data = [row
                   for row in csv_dic_reader
                ]
                for row in data:
                   read_obj.close()
                filesMove(csv_file, destination_file_path, src_file_path)
                if len(data) <= 1: # this will check no rows / content
                read_obj.close()
                filesMove(csv_file, error_file_path, src_file_path)

Suggestion : 4

Not closing a file after an interaction is not only a waste of program resources but could also prevent other file interactions and may lead to inconsistencies when running your scripts on different Python versions. Leaving files open is also widely regarded as poor practice, and it's always best to get into good habits early on.,Not only will using a context manager free you from having to remember to close files manually, but it will also make it much easier for others reading your code to see precisely how the program is using the file.,For anyone working with Python, interacting with files will be unavoidable. The simplest method for opening and closing files is below.,The updated code provides the same functionality with less coding required. Using a with open() statement will automatically close a file once the block has completed.

file = open('example_file.txt') # open the example file
file.close() # close it

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file = open('file_1.txt', 'r') # file is opened in read(r) mode
print(file.read())

file = open('file_1.txt', 'a') # file is opened in append(a) mode
file.write(' and we have read it.')

file = open('file_1.txt', 'r') # file is opened in read(r) mode
print(file.read())

file.close()

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This is file 1 text
This is file 1 text and we have read it.

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f1 = open('file_1.txt', 'r')
print(f1.read())

f2 = open('file_1.txt', 'a')
f2.write(' and we have read it.')

f3 = open('file_1.txt', 'r')
print(f3.read())

f1.close()
f2.close()
f3.close()

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This is file 1 text
This is file 1 text

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f1 = open('file_1.txt', 'r')
print(f1.read())
f1.close()

f2 = open('file_1.txt', 'a')
f2.write(' and we have read it.')
f2.close()

f3 = open('file_1.txt', 'r')
print(f3.read())
f3.close()

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