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string manipulation algorithm to find string greater than original string

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Given two strings str1 and str2 of same length N, the task is to check if there exists any permutation possible in any of the given strings, such that every character of one string is greater or equal to every character of the other string, at corresponding indices. Return true if permutation exists otherwise false.,Write a program to print all permutations of a given string,Writing code in comment? Please use ide.geeksforgeeks.org, generate link and share the link here.,If found lexicographically larger, print true, otherwise false.

true

Suggestion : 2

Example code:

def next_word(word):
   word = list(word)
seen = {}
for i in range(len(word) - 1, -1, -1):
   if any(x > word[i]
      for x in seen):
   x = min(x
      for x in seen
      if x > word[i])
word[i], word[seen[x]] = word[seen[x]], word[i]
return ''.join(word[: i + 1] + sorted(word[i + 1: ]))
if word[i] not in seen:
   seen[word[i]] = i

for word in ["hefg", "dhck", "dkhc", "fedcbabcd"]:
   print(word, next_word(word))

Result:

hefg hegf
dhck dhkc
dkhc hcdk
fedcbabcd fedcbabdc

Code

def next_lexicographical(word):
   word = list(word)

# Find the pivot and the successor
pivot = next(i
   for i in range(len(word) - 2, -1, -1) if word[i] < word[i + 1])
successor = next(i
   for i in range(len(word) - 1, pivot, -1) if word[i] > word[pivot])

# Swap the pivot and the successor
word[pivot], word[successor] = word[successor], word[pivot]

# Reverse the suffix
word[pivot + 1: ] = word[-1: pivot: -1]

# Reform the word and
return it
return ''.join(word)

Example

words = [
   'hefg',
   'dhck',
   'dkhc',
   'fedcbabcd'
]

for word in words:
   print(next_lexicographical(word))

Output

hegf
dhkc
hcdk
fedcbabdc

Suggestion : 3

find the position among i+1 ... n-1 containing the least symbol that's greater than s[i]; call this position j; in our case, j = 3;,sort all the characters after the that position to get the minimum string,Your problem can we reworded as finding anycodings_python the next lexicographical permutation of anycodings_python a string.,The above algorithm is especially anycodings_python interesting because it is O(n).

i have these inputs 

hefg
dhck
dkhc
fedcbabcd

which should output

hegf
dhkc
hcdk
fedcbabdc

How can I modify the algorithm To fix the anycodings_algorithm cases?

list1 = ['d', 'k', 'h', 'c']
list2 = []
maxVal = list1.index(max(list1))
for i in range(maxVal):
   temp = list1[maxVal]
list1[maxVal] = list1[i - 1]
list1[i - 1] = temp
list2.append(''.join(list1))
print(min(list2))

Example code:

def next_word(word):
   word = list(word)
seen = {}
for i in range(len(word) - 1, -1, -1):
   if any(x > word[i]
      for x in seen):
   x = min(x
      for x in seen
      if x > word[i])
word[i], word[seen[x]] = word[seen[x]], word[i]
return ''.join(word[: i + 1] + sorted(word[i + 1: ]))
if word[i] not in seen:
   seen[word[i]] = i

for word in ["hefg", "dhck", "dkhc", "fedcbabcd"]:
   print(word, next_word(word))

Result:

hefg hegf
dhck dhkc
dkhc hcdk
fedcbabcd fedcbabdc

Code

def next_lexicographical(word):
   word = list(word)

# Find the pivot and the successor
pivot = next(i
   for i in range(len(word) - 2, -1, -1) if word[i] < word[i + 1])
successor = next(i
   for i in range(len(word) - 1, pivot, -1) if word[i] > word[pivot])

# Swap the pivot and the successor
word[pivot], word[successor] = word[successor], word[pivot]

# Reverse the suffix
word[pivot + 1: ] = word[-1: pivot: -1]

# Reform the word and
return it
return ''.join(word)

Example

words = [
   'hefg',
   'dhck',
   'dkhc',
   'fedcbabcd'
]

for word in words:
   print(next_lexicographical(word))

Output

hegf
dhkc
hcdk
fedcbabdc

Suggestion : 4

45. Write a Python program to check whether a string contains all letters of the alphabet. Go to the editor Click me to see the sample solution,87. Write a Python program find the common values that appear in two given strings. Go to the editor Sample Output: Original strings: Python3 Python2.7 Intersection of two said String: Python Click me to see the sample solution,75. Write a Python program to find smallest window that contains all characters of a given string. Go to the editor Click me to see the sample solution,61. Write a Python program to remove duplicate characters of a given string. Go to the editor Click me to see the sample solution

The Any() Function:

>>> arrival_hours = {
      'Mon': 8.5,
      'Tue': 8.75,
      'Wed': 9,
      'Thu': 8.5,
      'Fri': 8.5
   } >>>
   arrival_checks = [x > 8.75
      for x in arrival_hours.values()
   ] >>>
   any(arrival_checks)
True

Suggestion : 5

5.3 Substring Search describes algorithms for searching for a substring in a large piece of text, including the classic Knuth-Morris-Pratt, Boyer-Moore, and Rabin-Karp algorithms. ,Palindrome check. Write a function that takes as input a string and returns true if the string is a palindrome, and false otherwise. A palindrome is a string that reads the same forwards or backwards. ,Concatenation. The + operator performs string concatenation. We avoid forming a string by appending one character at a time because that is a quadratic-time process in Java. (Java has a StringBuilder class for that use.) ,Watson-Crick complement. Write a function that takes as input a DNA string of A, C, G, and T characters and returns the string in reverse order with all of characters replaced by their complements. For example, if the input is ACGGAT, then return ATCCGT. 

public static String mystery(int N) {
   String s = "";
   while (N > 0) {
      if (N % 2 == 1) s = s + s + "x";
      else s = s + s;
      N = N / 2;
   }
   return s;
}
public static String mystery(String s, String t) {
   int N = s.length();
   if (N <= 1) return s + t;
   String a = mystery(s.substring(0, N / 2), t.substring(0, N / 2));
   String b = mystery(s.substring(N / 2, N), t.substring(N / 2, N));
   return a + b;
}
public static String reverse(String s) {
   int N = s.length();
   if (N <= 1) return s;
   String a = s.substring(0, N / 2);
   String b = s.substring(N / 2, N);
   return reverse(b) + reverse(a);
}
public static String random(int N) {
   if (N == 0) return "";
   if (N == 1) return 'A' + StdRandom.uniform(26);
   return random(N / 2) + random(N - N / 2);
}
public static int hex2decimal(String s) {
   String digits = "0123456789ABCDEF";
   s = s.toUpperCase();
   int val = 0;
   for (int i = 0; i < s.length(); i++) {
      char c = s.charAt(i);
      int d = digits.indexOf(c);
      val = 16 * val + d;
   }
   return val;
}

Suggestion : 6

Returns the string str, with the substring beginning at position pos and len characters long replaced by the string newstr. Returns the original string if pos is not within the length of the string. Replaces the rest of the string from position pos if len is not within the length of the rest of the string. Returns NULL if any argument is NULL. , Returns the string str with all occurrences of the string from_str replaced by the string to_str. REPLACE() performs a case-sensitive match when searching for from_str. , Returns the string str, left-padded with the string padstr to a length of len characters. If str is longer than len, the return value is shortened to len characters. , Returns the string str, right-padded with the string padstr to a length of len characters. If str is longer than len, the return value is shortened to len characters. If str, padstr, or len is NULL, the function returns NULL.

Returns the numeric value of the leftmost character of the string str. Returns 0 if str is the empty string. Returns NULL if str is NULL. ASCII() works for 8-bit characters. 

mysql > SELECT ASCII('2'); -
> 50
mysql > SELECT ASCII(2); -
> 50
mysql > SELECT ASCII('dx'); -
> 100

Returns a string representation of the binary value of N, where N is a longlong (BIGINT) number. This is equivalent to CONV(N,10,2). Returns NULL if N is NULL. 

mysql > SELECT BIN(12); -
> '1100'

Returns the length of the string str in bits. Returns NULL if str is NULL. 

mysql > SELECT BIT_LENGTH('text'); -
> 32

CHAR() interprets each argument N as an integer and returns a string consisting of the characters given by the code values of those integers. NULL values are skipped. 

mysql > SELECT CHAR(77, 121, 83, 81, '76'); +
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
|
CHAR(77, 121, 83, 81, '76') |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   |
   0x4D7953514C |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   1 row in set(0.00 sec)

mysql > SELECT CHAR(77, 77.3, '77.3'); +
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
|
CHAR(77, 77.3, '77.3') |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   |
   0x4D4D4D |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   1 row in set(0.00 sec)

By default, CHAR() returns a binary string. To produce a string in a given character set, use the optional USING clause: 

mysql > SELECT CHAR(77, 121, 83, 81, '76'
   USING utf8mb4); +
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
|
CHAR(77, 121, 83, 81, '76'
      USING utf8mb4) |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
   |
   MySQL |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
   1 row in set(0.00 sec)

mysql > SELECT CHAR(77, 77.3, '77.3'
   USING utf8mb4); +
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
|
CHAR(77, 77.3, '77.3'
      USING utf8mb4) |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   |
   MMM |
   + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- +
   1 row in set, 1 warning(0.00 sec)

mysql > SHOW WARNINGS; +
-- -- -- -- - + -- -- -- + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
|
Level | Code | Message |
   + -- -- -- -- - + -- -- -- + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
   |
   Warning | 1292 | Truncated incorrect INTEGER value: '77.3' |
   + -- -- -- -- - + -- -- -- + -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- - +
   1 row in set(0.00 sec)

CHAR() arguments larger than 255 are converted into multiple result bytes. For example, CHAR(256) is equivalent to CHAR(1,0), and CHAR(256*256) is equivalent to CHAR(1,0,0): 

mysql > SELECT HEX(CHAR(1, 0)), HEX(CHAR(256)); +
-- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- +
|
HEX(CHAR(1, 0)) | HEX(CHAR(256)) |
   + -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- +
   |
   0100 | 0100 |
   + -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- +
   1 row in set(0.00 sec)

mysql > SELECT HEX(CHAR(1, 0, 0)), HEX(CHAR(256 * 256)); +
-- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- +
|
HEX(CHAR(1, 0, 0)) | HEX(CHAR(256 * 256)) |
   + -- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- +
   |
   010000 | 010000 |
   + -- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- +
   1 row in set(0.00 sec)

Returns the length of the string str, measured in code points. A multibyte character counts as a single code point. This means that, for a string containing two 3-byte characters, LENGTH() returns 6, whereas CHAR_LENGTH() returns 2, as shown here: 

mysql > SET @dolphin: = '海豚';
Query OK, 0 rows affected(0.01 sec)

mysql > SELECT LENGTH(@dolphin), CHAR_LENGTH(@dolphin); +
-- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- -- - +
|
LENGTH(@dolphin) | CHAR_LENGTH(@dolphin) |
   + -- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- -- - +
   |
   6 | 2 |
   + -- -- -- -- -- -- -- -- -- + -- -- -- -- -- -- -- -- -- -- -- - +
   1 row in set(0.00 sec)

CONCAT() returns NULL if any argument is NULL. 

mysql > SELECT CONCAT('My', 'S', 'QL'); -
> 'MySQL'
mysql > SELECT CONCAT('My', NULL, 'QL'); -
> NULL
mysql > SELECT CONCAT(14.3); -
> '14.3'

For quoted strings, concatenation can be performed by placing the strings next to each other: 

mysql > SELECT 'My'
'S'
'QL'; -
> 'MySQL'


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