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while executing the below code i'm getting this 'typeerror: img is not a numerical tuple'

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You have changed the code while copying. Obviously, cam.read() returns a tuple. From the documentation:

Python: cv2.VideoCapture.read([image])→ retval, image

Try changing your code like this:

def get_image():
   _, cap = cam.read()
return cap

or, even better,

def get_image():
   return cam.read()[1]

Suggestion : 2

You have changed the code while copying. anycodings_opencv Obviously, cam.read() returns a tuple. anycodings_opencv From the documentation:,I have done everything right i didn't change anycodings_image-processing anything the code which when executed in a anycodings_image-processing seperate program it's not showing any error anycodings_image-processing but when run inside my code it's showing anycodings_image-processing error. The code i copied is from this link,if np.any( initial == None): #your anycodings_opencv code It will definitely work for you. anycodings_opencv The error in this code because initial anycodings_opencv is treated as a numpy array.,How do I build a script that allow me to target a tag with a new NPM version to be able to merge into one or more branches?

1._
    import cv2
    ram_frames = 30
    cam = cv2.VideoCapture(0)
    def get_image():
       cap = cam.read()
    return cap
    for i in xrange(ramp_frames):
       temp = get_image()
    image = get_image()
    cv2.imwrite('bin/color.jpg', image)

The error i'm getting is :

File "C:\modules\imlib.py", line 1035, in __init__
self.imin = self.WinWebCam()
File "C:\modules\imlib.py", line 1125, in WinWebCam
cv2.imwrite('bin/color.jpg', image)
TypeError: img is not a numerical tuple

You have changed the code while copying. anycodings_opencv Obviously, cam.read() returns a tuple. anycodings_opencv From the documentation:

Python: cv2.VideoCapture.read([image]) ⠆ ’ retval, image

Try changing your code like this:

def get_image():
   _, cap = cam.read()
return cap

or, even better,

def get_image():
   return cam.read()[1]

Suggestion : 3

Tags: opencv , python , python-2.7 , image-processing Answers: 1 | Viewed 11,706 times , 4 days ago Hilfe bei der Programmierung, Antworten auf Fragen / Python / Während ich den folgenden Code ausführe, erhalte ich diesen 'TypeError: img is not a numerical tuple' - Python, Python-2.7, OpenCV, Bildverarbeitung ,While Executing The Below Code Im Getting This Typeerror Img Is Not A Numeric, 1 week ago Answer to Solved While executing the code in below link Im getting a 


    import cv2 ram_frames = 30 cam = cv2.VideoCapture(0) def get_image(): cap = cam.read() return cap
    for i in xrange(ramp_frames): temp = get_image() image = get_image() cv2.imwrite('bin/color.jpg', image)

Python: cv2.VideoCapture.read([image])→ retval, image
    import cv2ram_frames = 30 cam = cv2.VideoCapture(0) def get_image(): cap = cam.read() return capfor i in xrange(ramp_frames): temp = get_image() image = get_image() cv2.imwrite('bin/color.jpg', image)
File "C:\modules\imlib.py", line 1035, in __init__self.imin = self.WinWebCam() File "C:\modules\imlib.py", line 1125, in WinWebCamcv2.imwrite('bin/color.jpg', image) TypeError: img is not a numerical tuple
Python: cv2.VideoCapture.read([image])→ retval, image
def get_image(): _, cap = cam.read() return cap

Suggestion : 4

Expected Ptrcv::UMat for argument ‘src’,I’m also having issues as well it’s giving this error: cv2.error: OpenCV(4.6.0) 👎 error: (-5:Bad argument) in function ‘CascadeClassifier’,I face this problem how to solve and where the repo for cloning:: Traceback (most recent call last): File “E:\Computer Vision\day2\string.py”, line 13, in color,thickness,cv2.LINE_AA) cv2.error: OpenCV(4.5.3) 👎 error: (-5:Bad argument) in function ‘rectangle’,cv2.error: OpenCV(4.6.0) 👎 error: (-5:Bad argument) in function ‘resize’

Probably it depends on the version of the dependencies, but if you face those type issues, just put coor = coor.astype(int) right after coor[3] = int(coor[3] * image_w) in L145 and remove the float casts np.float32 in L159 and L161.

cv2.rectangle(image, c1, c3, bbox_color, -1)
cv2.putText(image, bbox_mess, (c1[0], (c1[1] - 2)), cv2.FONT_HERSHEY_SIMPLEX,
      fontScale, (0, 0, 0), bbox_thick // 2, lineType=cv2.LINE_AA)

Suggestion : 5

asked 2018-03-01 16:47:01 -0500 , Asked: 2018-03-01 16:47:01 -0500 , Last updated: Mar 02 '18 , updated 2018-03-02 01:19:57 -0500

The following is my error:

     Traceback (most recent call last):
     File "cameraStitching.py", line 26, in <module>
        result = stitcher.stitch([left, right])
        TypeError: images is not a numerical tuple

Here is my code:

 #!/usr/bin/env python

 from __future__
 import print_function
 import stitcher
 #from imutils.video
 import VideoStream

 import numpy as np
 import datetime
 #import imutils
 import time
 import cv2
 import sys

 print("[INFO] starting cameras...")
 leftStream = cv2.VideoCapture("nvcamerasrc sensor-id=0 ! video/x-raw(memory:NVMM), width=(int)640, height=(int)480,format=(string)I420, framerate=(fraction)30/1 ! nvvidconv flip-method=0 ! video/x-raw, format=(string)BGRx ! videoconvert ! video/x-raw, format=(string)BGR ! appsink")
 rightStream = cv2.VideoCapture("nvcamerasrc sensor-id=2 ! video/x-raw(memory:NVMM), width=(int)640, height=(int)480,format=(string)I420, framerate=(fraction)30/1 ! nvvidconv flip-method=0 ! video/x-raw, format=(string)BGRx ! videoconvert ! video/x-raw, format=(string)BGR ! appsink")
 time.sleep(2.0)

 stitcher = cv2.createStitcher(False)
 total = 0

 while True:
    left = leftStream.read()
 right = rightStream.read()

 result = stitcher.stitch([left, right])

 if result is None:
    print("[INFO] homography could not be computed")
 break

 total += 1
 timeStamp = datetime.datetime.now()
 ts = timestamp.strftime("%A %d %B %Y %I:%M:%S%p")
 cv2.putText(result, ts, (10, result.shape[0] - 10),
    cv2.FONT_HERSHEY_SIMPLEX, 0.35, (0, 0, 255), 1)

 cv2.imshow("result", result)
 cv2.imshow("left frame", left)
 cv2.imshow("right frame", right)
 key = cv2.waitKey(1) & 0xFF

 if key == ord("q"):
    break

 print("[INFO] cleaning up...")
 cv2.destroyAllWindows()
 leftStream.stop()
 rightStream.stop()

both VideoCapture.read() and Stitcher.stitch() return a tuple of results. you need code like this:

left_img, left_ok = leftStream.read()
right_img, right_ok = leftStream.read()

if not left_ok:
   print("left cam failed")
return

if not right_ok:
   print("right cam failed")
return

status, result = stitcher.stitch([left_img, right_img])

Suggestion : 6

Lists are enclosed in square brackets ([ and ]) and tuples in parentheses (( and )).,A list containing no elements is called an empty list, and a tuple with no elements is an empty tuple.,In the case of lists or tuples, they are made up of elements, which are values of any Python datatype, including other lists and tuples.,The indexing operator ([ ]) selects a single element from a sequence. The expression inside brackets is called the index, and must be an integer value. The index indicates which element to select, hence its name.

[10, 20, 30, 40, 50]
["spam", "bungee", "swallow"]
(2, 4, 6, 8)
("two", "four", "six", "eight")[("cheese", "queso"), ("red", "rojo"), ("school", "escuela")]
>>> thing = 2, 4, 6, 8
>>> type(thing)
<class 'tuple'>
   >>> thing
   (2, 4, 6, 8)
>>> singleton = (2,)
>>> type(singleton)
<class 'tuple'>
   >>> not_tuple = (2)
   >>> type(not_tuple)
   <class 'int'>
      >>> empty_tuple = ()
      >>> type(empty_tuple)
      <class 'tuple'>
>>> fruit = "banana" >>>
   fruit[1]
'a' >>>
fruits = ['apples', 'cherries', 'pears'] >>>
   fruits[0]
'apples' >>>
prices = (3.99, 6.00, 10.00, 5.25) >>>
   prices[3]
5.25
   >>>
   pairs = [('cheese', 'queso'), ('red', 'rojo'), ('school', 'escuela')] >>>
   pairs[2]
   ('school', 'escuela')
>>> len('banana')
6
>>> len(['a', 'b', 'c', 'd'])
4
   >>>
   len((2, 4, 6, 8, 10, 12))
6
   >>>
   pairs = [('cheese', 'queso'), ('red', 'rojo'), ('school', 'escuela')] >>>
   len(pairs)
3

Suggestion : 7

Python is copyrighted. Like Perl, Python source code is now available under the GNU General Public License (GPL).,do not run import site to look for Python paths on startup,This chapter covers all the basic I/O functions available in Python 3. For more functions, please refer to the standard Python documentation.,You can use any Python source file as a module by executing an import statement in some other Python source file. The import has the following syntax −

For example, if we want Python 3.x's integer division behavior in Python 2, add the following import statement.

from __future__
import division

Most notable and most widely known change in Python 3 is how the print function is used. Use of parenthesis () with print function is now mandatory. It was optional in Python 2.

print "Hello World"
#is acceptable in Python 2
print("Hello World") # in Python 3, print must be followed by()

The print() function inserts a new line at the end, by default. In Python 2, it can be suppressed by putting ',' at the end. In Python 3, "end =' '" appends space instead of newline.

print x, # Trailing comma suppresses newline in Python 2
print(x, end = " ") # Appends a space instead of a newline in Python 3

Python 2 accepts both notations, the 'old' and the 'new' syntax; Python 3 raises a SyntaxError if we do not enclose the exception argument in parenthesis.

raise IOError, "file error"
#This is accepted in Python 2
raise IOError("file error") #This is also accepted in Python 2
raise IOError, "file error"
#syntax error is raised in Python 3
raise IOError("file error") #this is the recommended syntax in Python 3

In Python 3, arguments to exception should be declared with 'as' keyword.

except Myerror, err: # In Python2
except Myerror as err: #In Python 3


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